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24 August, 04:39

How many 5-digit (positive) even numbers can be formed using the digits 4, 6, 7, 2, 8 if digits can be repeated?

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  1. 24 August, 04:54
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    In this problem, since the digits can be repeated, you have to know how many possible digit can be used in every digit of a five - digit number. On the first digit of the number, there are 5 possible digits. The second digit of the number has 5 possible digits as well. The third digit of the number has 5 possible digits. The fourth and the fifth digit will have 5 possible digits as well. Multiplying the possible digits for each digit of a five - digit number:

    5 x 5 x 5 x 5 x 5 = 3,125 possible five - digit numbers
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