What is the axis of symmetry of y = - (x+10) ^2-9

Y=*^2-9

Step-by-step explanation:

(X+0) ^2-9

Use the vertex form, y=a (x-h) ^2+k

a=1

h=0

k=-9

And because the parabola opens up the vertex is (0,-9)

The distance from the vertex to a focus of the parabola by using the __ 1/4a__ formula:

1/4 (1)

1/4

(h, k+p)

(0,-35/4)