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2 March, 12:36

Solve for x: 3/3x + 1/x+4 = 10/7x

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  1. 2 March, 13:01
    0
    Given,

    3/3x + 1 / (x + 4) = 10/7x

    1/x + 1 / (x+4) = 10/7x

    Because the first term on LHS has 'x' in the denominator and the second term in the LHS has ' (x + 4) ' in the denominator. So to get a common denominator, multiply and divide the first term with ' (x + 4) ' and the second term with 'x' as shown below

    { (1/x) (x + 4) / (x + 4) } + { (1 / (x + 4)) (x/x) } = 10/7x

    { (1 (x + 4)) / (x (x + 4)) } + { (1x) / (x (x + 4)) } = 10/7x

    Now the common denominator for both terms is (x (x + 4)); so combining the numerators, we get,

    {1 (x + 4) + 1x} / {x (x + 4) } = 10/7x

    (x + 4 + 1x) / (x (x + 4)) = 10/7x

    (2x + 4) / (x (x + 4)) = 10/7x

    In order to have the same denominator for both LHS and RHS, multiply and divide the LHS by '7' and the RHS by ' (x + 4) '

    { (2x+4) / (x (x + 4)) } (7 / 7) = (10 / 7x) { (x + 4) / (x + 4) }

    (14x + 28) / (7x (x + 4)) = (10x + 40) / (7x (x + 4))

    Now both LHS and RHS have the same denominator. These can be cancelled.

    ∴14x + 28 = 10x + 40

    14x - 10x = 40 - 28

    4x = 12

    x = 12/4

    ∴x = 3
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