We have enough material to build a fence around a station that has a perimeter of 180 feet. The width of the rectangular space must be 30 1/4 feet. What must the length be?

Question

Jose Villa

Mathematics

14 May, 21:23

We have enough material to build a fence around a station that has a perimeter of 180 feet. The width of the rectangular space must be 30 1/4 feet. What must the length be?

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Answers (1)

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Shepherd · Answer 1

To solve this problem you must use the formula of the perimeter (P) of a rectangle and clear the length (L). The perimeter of a rectangle, is:

P=2L+2W

"P" is the perimeter of the rectangle (P=180 feet).

"L" is the lenght of the rectangle.

"W" is the widht of the rectangle (W = 30 1/4 feet=30.25 feet).

As you can see, you already have the value of the perimeter (P) and the value of the widht (W). Now, you can clear the lenght (L):

P=2L+2W

2L=P-2W

L = (P-2W) / 2

When you substitute the values, you obtain:

L = (P-2W) / 2

L = (180 feet-2x30.25 feet) / 2

L = (119.5 feet) / 2

L=59.75 feet

What must the length be?

The answer is: 59.75 feet