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30 July, 05:28

If f (x) = x^2+1 and g (x) = x-4, which value is equivalent to (f*g) (10) ?

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  1. 30 July, 05:30
    0
    (F*g) (10)

    F (10) = 10^2+1 and g (10) = 10-4

    100+1 and 6

    F (10) = 101

    G (10) = 6

    (F*g) = 101*6

    (f*g) = 606
  2. 30 July, 05:41
    0
    F*g (x) = (x^2+1) (x-4)

    f*g (x) = x^3+x-4-4x^2

    Then plug in x

    (10) ^3 + (10) - 4-4 (10) ^2

    1000+10-4-4*100

    1006-400

    606
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