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17 September, 03:36

Differentiate the function g (x) = ln[x (sqrt (x^2 - 1)) ]

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  1. 17 September, 03:56
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    G (x) = ln[x (sqrt (x^2 - 1)) ]

    g' (x) = 1/[x (sqrt (x^2 - 1)) ] * (x^2/sqrt (x^2 - 1) + sqrt (x^2 - 1)) = ((x^2 + x^2 - 1) / sqrt (x^2 - 1)) / x (sqrt (x^2 - 1)) = (2x^2 - 1) / x (x^2 - 1) = (2x^2 - 1) / (x^3 - x)
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