You have a bag of 12 blue marbles and 12 red marbles. each are labeled 1-12. so you have 24 marbles in total (1-12 for each color).

you draw one at random, put it back in the bag, and draw the second one.

what is the probability of the first marble being blue and the second marble being red?

Question

Tyrese Bradford

Mathematics

28 December, 00:38

You have a bag of 12 blue marbles and 12 red marbles. each are labeled 1-12. so you have 24 marbles in total (1-12 for each color).

you draw one at random, put it back in the bag, and draw the second one.

what is the probability of the first marble being blue and the second marble being red?

+2

Answers (2)

Know the Answer?

Eduardo Carr · Answer 1

the probability of you drawing a blue first then drawing a red would be a 50/50 chance with 50 leaning toward you meaning it's very high but might not happen as well

Ball · Answer 2

The probability of the first marble being blue and second being red is a 50/50 because you have 12 red and 12 blue so 50/50

You have a bag of 12 blue marbles and 12 red marbles. each are labeled 1-12. so you have 24 marbles in total (1-12 for each color).you draw one at random, put it back in the bag, and draw the second one.what is the probability of the first marble being blue and the second marble being red?

You have a bag of 12 blue marbles and 12 red marbles. each are labeled 1-12. so you have 24 marbles in total (1-12 for each color).

you draw one at random, put it back in the bag, and draw the second one.

what is the probability of the first marble being blue and the second marble being red?