In a different plan for area codes, the first digit could be any number from 4 through 8 , the second digit was either 3, 4, 5, or 6 , and the third digit could be any number exceptnbsp 2 or 5. with this plan, how many different area codes are possible?

Question

Brent Nash

Mathematics

26 March, 17:47

In a different plan for area codes, the first digit could be any number from 4 through 8 , the second digit was either 3, 4, 5, or 6 , and the third digit could be any number exceptnbsp 2 or 5. with this plan, how many different area codes are possible?

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Aspen Raymond · Answer 1

For the first digit, we have 5 options that are 4,5,6,7,8. For the second digit, we have 4 options which are 3,4,5 or 6 and for the third digit, we have the options of all numbers except 2 or 5 that is 1,3,4,6,7,8,9,0. SO we have 8 options for third digit. So to find the total number of options, we need to multiply all the possible options for each digit that is 5 times 4 times 8 = 160. So the number of possible options are 160.