Find the horizontal asymptote of f (x) = x^2+6x-8/x-8

Question

Joselyn Ward

Mathematics

24 September, 07:41

Find the horizontal asymptote of f (x) = x^2+6x-8/x-8

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Answers (2)

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Randall Drake · Answer 1

Randall Drake 24 September, 07:58

0

Look at the definitiioin

Hazel Nunez · Answer 2

1. If nm n>m, then there is no horizontal asymptote (there is an oblique asymptote). x2 - 6 x + 8 x2 - x - 12 x2 - 6 x + 8 x2 - x - 12 Find nn and mm. n=2 n=2 m=2 m=2 Since n=m n=m, the horizontal asymptote is the line y = ab y = ab where a=1 a=1 and b=1 b=1. y=1 y=1 There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator. No Oblique AsymptotesThis is the set of all asymptotes. Vertical Asymptotes: x = - 3 x = - 3 Horizontal Asymptotes: y = 1