Ask Question
2 June, 18:30

If a rock is thrown upward on the planet Mars with a velocity of 10 m/s, its height (in meters) after t seconds is given by H = 10t - 1.86t2. Find Velocity after 2 seconds. Find velocity of rock when x=a. When rock hits surface?

+3
Answers (1)
  1. 2 June, 18:42
    0
    An expression for the velocity can be obtained by differentiating the distance term with respect to time. Therefore

    dH/dt = v = 10 - 3.72t

    substituting t = 2 sec

    v = 10 - 3.72 (2)

    v = 2.56 m/s, velocity after 2 hours

    Since there is no variable x in the problem, I assumed that x = t = a

    therefore at t = a

    v = 10 - 3.72a^2

    when the rock hits the surface:

    when the rock reaches the top, the velocity is equal to zero

    therefore the expression becomes, H = 1.86t2

    dH/dt = v = 3.72t

    when the rock hits the surface H = 10 therefore t = 2.32 s

    @t = 2.32 s

    v = 3.72*2.32 = 8.63 m/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “If a rock is thrown upward on the planet Mars with a velocity of 10 m/s, its height (in meters) after t seconds is given by H = 10t - ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers