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15 April, 08:53

The length of a rectangle is 7 yd more than double the width, and the area of the rectangle is 99 yd^2. find the dimensions of the rectangle.

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  1. 15 April, 09:02
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    w (2w+7) = 99

    2w^2 + 7w - 99 = 0

    (2w - 11) (w + 9) = 0

    w+9=0 results in negative measures

    2w-11 = 0

    2w = 11

    w = 11/2 = 5.5

    L = 2w + 7 = 18
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