Rate = k[xy2][z2] select a possible mechanism for the reaction. consider the reaction which has a rate law of select a possible mechanism for the reaction. a step1:step2:step3:z2→z+z (slow) xy2+z→xy2z (fast) xy2+z→xy2z (fast) b step1:step2:xy2+z2→xy2z+z (slow) xy2+z→xy2z (fast) c step1:step2:xy2+z2→xy2z2 (slow) xy2z2→xy2z+z (fast)

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Hood

Mathematics

3 July, 23:55

Rate = k[xy2][z2] select a possible mechanism for the reaction. consider the reaction which has a rate law of select a possible mechanism for the reaction. a step1:step2:step3:z2→z+z (slow) xy2+z→xy2z (fast) xy2+z→xy2z (fast) b step1:step2:xy2+z2→xy2z+z (slow) xy2+z→xy2z (fast) c step1:step2:xy2+z2→xy2z2 (slow) xy2z2→xy2z+z (fast)

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Eleanor Wiley · Answer 1

The answer is C

Step1: xy2+z2→xy2z2 (slow)

Step2: xy2z2→xy2z+z (fast)

2XY 2 + Z 2 → 2XY 2 Z

Rate = k[xy2][z2]

When the two elementary steps are summed up, the result is equivalent to the stoichiometric equation. Hence, this mechanism is acceptable. The order of both elementary steps is 2, which is ‘≤3’; this also makes this mechanism acceptable. Furthermore, the rate equation aligns with the experimentally determined rate equation, and this also makes this mechanism acceptable. Therefore, since all the three rules have been observed, this mechanism is possible.