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3 August, 03:05

Find three consecutive even integers such that the product of the first and the third is 96

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  1. 3 August, 03:33
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    Step-by-step explanation:

    x, x+2, x+4 are the consecutive even integers

    x (x+4) = 96

    X^2 + 4x = 96

    x^2 + 4x = 96

    x^2 + 12x-8x - 96=0

    x (x+12) - 8 (x+12) = 0

    (x+12) (x-8) = 0

    Therefore x=8 or-12

    x=8

    Consecutive even integers are 8,10,12
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