Find three consecutive even integers such that the product of the first and the third is 96

Step-by-step explanation:

x, x+2, x+4 are the consecutive even integers

x (x+4) = 96

X^2 + 4x = 96

x^2 + 4x = 96

x^2 + 12x-8x - 96=0

x (x+12) - 8 (x+12) = 0

(x+12) (x-8) = 0

Therefore x=8 or-12

x=8

Consecutive even integers are 8,10,12