Box A contained only 50-cent coins while Box B contained only 20 cents coins. Box B has 60 more coins than Box A but the value of all the coins in Box A is $4.50 more than the value of all the coins in Box B. Find the amount of money in Box A.

x numbers of coins in box A = 55

y numbers of coins in box B = 115

Step-by-step explanation:

the numbers of coins in box y = x + 60

the value in cent of $ in box A is 50*x

and the value in cent of $ in box B is 20*y

So 50*x = 20*y + 450

y = 60 + x

Solving for x 50x = 20 * (60+x) + 450 50x = 1200 + 20x + 450

30x = 1650 x = 55

y = 60 + 55 = 115