On a game show, contestants must arrange the digits 3, 4, and 5 in the proper order to form the price of an appliance. When the contestant arranges the digits correctly, he or she wins the appliance. What is the probability of winning when the contestant knows that the price is at least $400?

Question

Eddie Arias

Mathematics

15 April, 16:29

On a game show, contestants must arrange the digits 3, 4, and 5 in the proper order to form the price of an appliance. When the contestant arranges the digits correctly, he or she wins the appliance. What is the probability of winning when the contestant knows that the price is at least $400?

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Answers (1)

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Brock Bell · Answer 1

25%

Step-by-step explanation:

The first thing is to identify the digits of 400, being 0 the first, the other 0 the second and the last digit would be 4, therefore, to make it less than 400, we have the following options:

1 choice for 3rd digit, can only value 3, because 4 and 5 would be greater than 400.

For the first and second digits it would be the same, two options, 4 or 5, no matter what. That is to say:

2 choices (4,5) for 1st digit

2 choices (4,5) for 2nd digit

Therefore, so 4 possible options out of which 1 is correct

P = 1/4 = 0.25

P = 25%