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2 September, 15:47

What are the first four terms of the sequence: f (n) = 3n (n+3)

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  1. 2 September, 16:11
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    First four terms would be n = 1, 2, 3, 4

    f (1) = 3 (1) (1 + 3)

    = 3 * 4

    =12

    f (2) = 3 (2) (2 + 3)

    = 6 * 5

    = 30

    f (3) = 3 (3) (3 + 3)

    = 9 * 6

    = 54

    f (4) = 3 (4) (4 + 3)

    = 12 * 7

    = 84
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