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29 September, 08:52

What is the quotient of

y-5/sqrt{2y^2-7y-15}

A. 2y + 3

B. 2y - 3

C. 2y - 17y R - 70

D. 2y - 17y R 70

+3
Answers (2)
  1. 29 September, 08:59
    0
    I think its A
  2. 29 September, 09:02
    0
    None of these

    Step-by-step explanation:

    y-5/√ (2y2 - 7y - 15)

    On simplifying 2y2 - 7y - 15, we get

    2y2 - (10-3) y - 15

    = 2y2 - 10y - 3y-15

    = 2y (y-5) - 3 (y-5)

    = (2y-3) (y-5)

    On squaring nominator and denominator we get

    (y-5) 2 / (2y-3) (y-5)

    = (y-5) / (2y-3)

    So the quotient becomes, 5/2

    While the remainder becomes 2.5
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