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21 March, 12:17

Find the limit as x approaches infinity of y=arccos (1+x21+2x2) y=arccos ((1+x^2) / (1+2x^2)) ?

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  1. 21 March, 12:39
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    If x approach infinity then (x² + 1) / (2x² + 1) = 1/2 then lim as x approach infinity

    lim y = arccos 1/2 = 1.047
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