In the xy-coordinate plane, the graph of the equation y=2x^2-12x-32 has zeros at x=d and x=e, where d>e. The graph has a minimum at (f,-50) what are the vaules of d, e, and f?

Question

Jacey Evans

Mathematics

30 January, 01:13

In the xy-coordinate plane, the graph of the equation y=2x^2-12x-32 has zeros at x=d and x=e, where d>e. The graph has a minimum at (f,-50) what are the vaules of d, e, and f?

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Answers (1)

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Jake Jones · Answer 1

To find the zeroes solve fro x:-

2 (x^2 - 6x - 16) = 0

2 (x - 8) (x + 2) = 0

x = {8, - 2

so d = 8 and e = - 2

the x coordinate of the minimum value = - b / 2a = 12 / 2*2 = 3

f = 3