A square hamburger is centered on a circular bun and the burger have an area of 16 square inches.

A-How far, to the nearest hundredth of an inch, does each corner of the burger stick out from the bun? Explain.

B-How far does the bun stick out from the center of each side of the burger?

C-Are the distances in part a and b equal? If not, which sticks out more, the burger or the bun? Explain.

Question

Andres Galloway

Mathematics

11 August, 05:21

A square hamburger is centered on a circular bun and the burger have an area of 16 square inches.

A-How far, to the nearest hundredth of an inch, does each corner of the burger stick out from the bun? Explain.

B-How far does the bun stick out from the center of each side of the burger?

C-Are the distances in part a and b equal? If not, which sticks out more, the burger or the bun? Explain.

+2

Answers (1)

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Gavin Combs · Answer 1

The square has sides of 4 inches, because 4*4=16. The radius of the circle is 4/√π. Because of the 45/45/90 triangle rules, we know that the diagonal of the square is 4√2. Half of 4√2 is 2√2. This half-diagonal overlaps with a radius of the circle; the radius is smaller because the corner sticks out. The answer is 2√2 - (4/√π). Use a calculator to find √2 and √π in 'rational' numbers, and solve it from there. For part B, you know that half the side of the circle is 2, and a radius would overlap with that. So that answer is 4/√π - 2. After you solve out those answers, you'll have part C