Ask Question
23 September, 19:21

What is the factorization of the expression below?

16x^2 - 49

A. (8x + 7) (2x-7)

O B. (4x + 7) (4x - 7)

O C. (8x-7) (2x-7)

O D. (4x-7) (4x-7)

+2
Answers (2)
  1. 23 September, 19:33
    0
    B

    Step-by-step explanation:

    There is no number between 16x and 49. So only think about the number being squared for 49; which is 7.

    Then 49 is negative, so you must have both positive and negative signs in both parenthesis. Otherwise, positive times positive is positive, and negative times negative is also positive.

    4x4 is 16. That's why you put fours in front of Xs.

    I am sorry for getting this wrong (if i did)
  2. 23 September, 19:47
    0
    B

    Step-by-step explanation:

    16 x² - 49 ← is a difference of squares and factors in general as

    a² - b² = (a + b) (a - b), thus

    16x² - 49

    = (4x) ² - 7²

    = (4x + 7) (4x - 7) → B
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What is the factorization of the expression below? 16x^2 - 49 A. (8x + 7) (2x-7) O B. (4x + 7) (4x - 7) O C. (8x-7) (2x-7) O D. (4x-7) ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers