Write the standard equation of a circle that passes through (1, - 6) with center (7, - 2).

A: (x + 1) 2 + (y - 6) 2 = 52

B: (x + 7) 2 + (y - 2) 2 = 52

C: (x - 1) 2 + (y + 6) 2 = 52

D: (x - 7) 2 + (y + 2) 2 = 52

Question

Coby Thornton

Mathematics

9 November, 20:40

Write the standard equation of a circle that passes through (1, - 6) with center (7, - 2).

A: (x + 1) 2 + (y - 6) 2 = 52

B: (x + 7) 2 + (y - 2) 2 = 52

C: (x - 1) 2 + (y + 6) 2 = 52

D: (x - 7) 2 + (y + 2) 2 = 52

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Answers (1)

Know the Answer?

Leandro Kaiser · Answer 1

D: (x - 7) 2 + (y + 2) 2 = 52

Step-by-step explanation:

Circle: (x - h) ² + (y - k) ² = r² center (h, k) r: radius

(1, - 6) on the circle: radius √ (1 - 7) ² + (-6 - (-2)) ² = √36 + 16 = √52

(x - 7) ² + (y + 2) ² = (√52) ² = 52

Write the standard equation of a circle that passes through (1, - 6) with center (7, - 2).A: (x + 1) 2 + (y - 6) 2 = 52B: (x + 7) 2 + (y - 2) 2 = 52C: (x - 1) 2 + (y + 6) 2 = 52D: (x - 7) 2 + (y + 2) 2 = 52

Write the standard equation of a circle that passes through (1, - 6) with center (7, - 2).

A: (x + 1) 2 + (y - 6) 2 = 52

B: (x + 7) 2 + (y - 2) 2 = 52

C: (x - 1) 2 + (y + 6) 2 = 52

D: (x - 7) 2 + (y + 2) 2 = 52