Ask Question
15 November, 15:41

Suppose that you are running a concession stand when a person gives you $18 and asks for six soft drinks and as many hot dogs as the remaining money will buy. If soft drinks are $1.00 and hot dogs are $1.75, what is the maximum number of hot dogs the person can buy?

+3
Answers (2)
  1. 15 November, 15:55
    0
    the max number of hot dogs he can buy is 6 with change left

    Step-by-step explanation:

    18.00 - 6.00 = 12.00 / 1.75 = 6.8
  2. 15 November, 16:00
    0
    Answer: 6 hot dogs

    Step-by-step explanation:

    The person gave you $18, first, we will charge the six soft drinks, that each one costs $1

    So the six drinks cost $6

    the remaining money is $18 - $6 = $12

    Now, with the $12 the customer wants to buy hot dogs, that each cost $1.75

    The number of hot dogs can be obtained by dividing the total money by the price of a hot dog:

    N = $12/1.75 = 6.8

    But you can not buy an 0.8 of a hot dog, so we must round to the whole number:

    N = 6

    So the maximum number of hot dogs that the money can buy is 6
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Suppose that you are running a concession stand when a person gives you $18 and asks for six soft drinks and as many hot dogs as the ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers