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22 October, 13:29

Find the derivative of g (t) = 3t^2+2t at t=-1 algebraically

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  1. 22 October, 13:31
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    8.

    Step-by-step explanation:

    If y = ax^n then the derivative y' = anx^ (n-1)

    g (t) = 3t^2 + 2t so the derivative g' (t)

    2*3 t^ (2-1) + 2t (1-1)

    = 6t + 2

    At t = 1 its value is 6 + 2 = 8.
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