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25 February, 08:46

Find the HCF and LCM of 306 and 54. Verify that HCF * LCM = Product of the two numbers.

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  1. 25 February, 08:51
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    306=2*153=2*3*51=2*3*3*17

    54=2*27=2*3*9=2*3*3*3,

    so 306 = 2*3*3*17, and 54 = 2*3*3*3

    GCF we are looking for all factors that belong to both of these numbers, that are common for both numbers.

    306 = 2*3*3*17,

    54 = 2*3*3*3

    GCF = 2*3*3

    LCM should include all factors that belong as first as second numbers, and we take prime factor from the number that has maximum repetition of it

    306 = 2*3*3*17

    54=2*3*3*3

    We can see 2 - one time, 3 - 3 times, and 17 - one time

    LCM = 2*3*3*3*17

    Product of two numbers : 306*54 = (2*3*3*17) * (2*3*3*3) = 2²*2⁵*17

    HCF*LCM = (2*3*3) * (2*3*3*3*17) = 2²*3⁵*17

    So we can see that

    Product of two numbers = HCF*LCM=2²*3⁵*17

    If you need you can calculate

    306 = 2*3*3*17,

    54 = 2*3*3*3

    GCF = 2*3*3=18

    LCM = 2*3*3*3*17=918

    GCF*LCM=18*918=16524

    Product of 306*54 = 16524
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