Write the following expression as a single

logarithm with coefficient 1.

log3 (6c) + log3 1/12

Answer: the answer is log3 (c/2)

log3 {c/2}

Step-by-step explanation:

Addiing two logs together is equivalent to multiplying their arguments.

Thus,

log3 (6c) + log3 1/12 = log3 6*c*[1/12], or log3 (log3 [6c][1/12]).

This simplifies to log3 {c/2} because 6c (1/12) = c/2