Ask Question
24 August, 22:47

Prove that the difference of the squares of 2 consecutive numbers is always the sum of the 2 numbers

+4
Answers (1)
  1. 24 August, 23:15
    0
    see explanation

    Step-by-step explanation:

    let the 2 consecutive numbers be n and n + 1

    sum = n + n + 1 = 2n + 1

    and

    (n + 1) ² - n² ← difference of the squares

    = n² + 2n + 1 - n²

    = 2n + 1 = sum of 2 numbers
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Prove that the difference of the squares of 2 consecutive numbers is always the sum of the 2 numbers ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers