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15 September, 11:06

Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 104 miles in the same time that Dana travels 96 miles. If Chuck's rate of travel is 4 mph more than Dana's, at what speed does Chuck travel?

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  1. 15 September, 11:28
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    Answer: Chuck's travel at a rate of 52mph

    Step-by-step explanation:

    For Chuck's trip:

    D=RT

    104 = (R+4) T

    T = 104 / (R+4)

    For Dana's trip:

    96 = RT

    T = 96/R

    Set both equation for Chuck's and Dana together

    104 / (R+4) = 96/R

    Then we cross multiply

    96 (R+4) = 104R

    96R + 384 = 104R

    104R - 96R = 384

    8R = 384

    To get R, divide both side by 8

    8R/8 = 384/8

    R = 48mph

    This means Dana's speed is 48mph

    Chuck's speed will be: 48mph+4mph = 52mph
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