Tickets to the school dance cost $3.00 in advance or $5.00 at the

door. There were a total of 184 tickets sold, raising $688. How many tickets

were sold at the door?

68 tickets

Step-by-step explanation:

This is a problem that involves a system of equations, the first step is to define your variables and write equations to represent the situation.

x = number of advance tickets

y = number of door tickets

x + y = 184

3x + 5y = 688

Next, you need to solve for one variable, based on how these equations are written, the best method would be to solve by multiplication.

-3 (x + y = 184) (multiply equation by - 3)

-3x - 3y = - 552

Now we need to combine the two equations together

3x + 5y = 688

-3x - 3y = - 552

From here we can eliminate the x variable when subtracting the equations, this results in:

2 y = 136

y = 68

Therefore, 68 tickets were sold at the door.