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Alannah Mcmillan
Mathematics
20 July, 15:15
In the nth term of a sequence is n2+50
what are the first 3 terms
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Aydan Blanchard
20 July, 15:29
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Would assume this to be: n² + 50
First term, n=1, n² + 50 = 1² + 50 = 1*1 + 50 = 1 + 50 = 51
Second term, n=2, n² + 50 = 2² + 50 = 2*2 + 50 = 4 + 50 = 54
Third term, n=3, n² + 50 = 3² + 50 = 3*3 + 50 = 9 + 50 = 59
First three terms are: 51, 54, & 59.
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