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20 July, 15:15

In the nth term of a sequence is n2+50

what are the first 3 terms

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  1. 20 July, 15:29
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    Would assume this to be: n² + 50

    First term, n=1, n² + 50 = 1² + 50 = 1*1 + 50 = 1 + 50 = 51

    Second term, n=2, n² + 50 = 2² + 50 = 2*2 + 50 = 4 + 50 = 54

    Third term, n=3, n² + 50 = 3² + 50 = 3*3 + 50 = 9 + 50 = 59

    First three terms are: 51, 54, & 59.
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