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2 October, 19:56

How do you factor 30n^2b-87nb+30b?

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  1. 2 October, 20:23
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    It's not clear whether you meant 30n^ (2b) or [30n^2] b.

    I will assume the latter.

    b can then be factored out of all three terms, resulting in

    b [30n^2 - 87n + 30] = b [ 3 ] [10n^2 - 29n + 10 ]

    Can you factor this further?
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