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15 April, 09:12

2x²+5=13

How do you find the value of x?

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Answers (2)
  1. 15 April, 09:27
    0
    Since 5 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 5 from both sides.

    2 x^2 = - 5 + 13

    Add - 5 and 13 to get 8.

    2 x^2 = 8

    Divide each term in the equation by 2.

    x^2 = 4

    Take the square root of both sides of the equation to eliminate the exponent on the left-hand side.

    x=± √4

    Rewrite 4 as 2^2

    x=± √ 2^2

    Pull terms out from under the radical.

    x=±2

    First, use the positive value of the ± to find the first solution.

    x=2

    Next, use the negative value of the ± to find the second solution.

    x=-2

    x=2,-2
  2. 15 April, 09:38
    0
    2x²+5=13

    subtract the 5 on both sides

    2x²=8

    divide by 2 on both sides

    x²=4

    put each side under the radical because of the exponent 2

    √x²=√4

    the radical cancels out the exponent 2; √4 = 2

    x=2
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