What is the standard form of this function?

f (x) = (x - 2) 2 + 6

A. f (x) = - x2 - 8x + 10

B. f (x) = - x2 - 6x + 10

C. f (x) = x2 - 8x + 10

D. f (x) = x2 - 4x + 10

D

Step-by-step explanation:

To find the standard function, open the bracket

f (x) = (x-2) ^2 + 6

(x-2) ^2 becomes

x (x-2) - 2 (x-2)

= x^2 - 2x - 2x + 4

= x^2 - 4x + 4

Now add 6 and it becomes x^2 - 4x + 4 + 6

= x^2 - 4x + 10