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19 October, 23:39

Compute (2i-6) (5+1) where i=√1

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Answers (2)
  1. 20 October, 00:07
    0
    4i - 32

    Step-by-step explanation:

    (2i-6) (5+i)

    10i - 30 + 2i² - 6i

    i=√-1

    i² = - 1

    10i - 30 + 2 (-1) - 6i

    -30 - 2 + 10i - 6i

    -32 + 4i

    4i - 32
  2. 20 October, 00:09
    0
    Step-by-step explanation:

    hello:

    (2i-6) (5+i) = 10i+2i²-30-6i ... i² = - 1

    (2i-6) (5+i) = 10i-2-30-6i = - 32+4i
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