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13 May, 08:01

The area of a playground is 336 yd2. The width of the playground is 5 yd longer than its length. Find the length and width of the playground

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  1. 13 May, 08:02
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    L=16

    W=21

    Set up a systems of equations:

    x=length

    y=width

    xy=336

    x+5=y

    Use substitution to solve:

    x (x+5) = 336

    x^2+5x=336

    Solve using factoring:

    x^2+5x-336=0

    (x-16) (x+21) = 0

    x=16 and x = - 21

    Since length can't be negative, l=16

    To find width, plug length into the first equation:

    (16) y=336

    y=21

    So ...

    L=16

    W=21
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