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23 January, 12:56

If x + y = 7 and xy = 4, then find the value of x^2 + y^2.

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  1. 23 January, 13:07
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    X+y=7

    xy=4

    in xy=4, divide both sides by any variable (lets say i divide it y y)

    xy=4

    x=4/y

    Now substitute it to the 1st equation

    x+y=7

    4/y+y=7

    Multiply both sides by y

    4+y^2=7y

    Change to standard form

    y^2-7y=4

    Use the square of something ...

    y^2-7y+49/4=4+49/4

    (y+7/2) ^2=65/4

    Squareroot both sides

    y+7/2=posinega (sqrt of 65) / 2

    y = (sqrt of 65) / 2-7/2

    or y = - (sqrt of 65) / 2-7/2
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