Solve the system of linear equations. separate the x - and y - values with a coma.

7x-3y=37

14x+11y=23

Solve the following system:

{7 x - 3 y = 37 | (equation 1)

{14 x + 11 y = 23 | (equation 2)

Swap equation 1 with equation 2:

{14 x + 11 y = 23 | (equation 1)

{7 x - 3 y = 37 | (equation 2)

Subtract 1/2 * (equation 1) from equation 2:

{14 x + 11 y = 23 | (equation 1)

{0 x - (17 y) / 2 = 51/2 | (equation 2)

Multiply equation 2 by 2/17:

{14 x + 11 y = 23 | (equation 1)

{0 x - y = 3 | (equation 2)

Multiply equation 2 by - 1:

{14 x + 11 y = 23 | (equation 1)

{0 x+y = - 3 | (equation 2)

Subtract 11 * (equation 2) from equation 1:

{14 x+0 y = 56 | (equation 1)

{0 x+y = - 3 | (equation 2)

Divide equation 1 by 14:

{x+0 y = 4 | (equation 1)

{0 x+y = - 3 | (equation 2)

Collect results:

Answer: {x = 4

{y = - 3