The distance traveled, in feet, of a ball dropped from a tall building is modeled by the equation d (t) = 16t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. What does the average rate of change of d (t) from t = 2 to t = 5 represent?

Answer Choices:

a. The ball travels an average distance of 112 feet from 2 seconds to 5 seconds.

b. The ball falls down with an average speed of 48 feet per second from 2 seconds to 5 seconds.

c. The ball falls down with an average speed of 112 feet per second from 2 seconds to 5 seconds.

d. The ball travels an average distance of 48 feet from 2 seconds to 5 seconds.

Question

Solomon Avila

Mathematics

9 July, 18:53

The distance traveled, in feet, of a ball dropped from a tall building is modeled by the equation d (t) = 16t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. What does the average rate of change of d (t) from t = 2 to t = 5 represent?

Answer Choices:

a. The ball travels an average distance of 112 feet from 2 seconds to 5 seconds.

b. The ball falls down with an average speed of 48 feet per second from 2 seconds to 5 seconds.

c. The ball falls down with an average speed of 112 feet per second from 2 seconds to 5 seconds.

d. The ball travels an average distance of 48 feet from 2 seconds to 5 seconds.

+3

Answers (1)

Know the Answer?

Kody Collins · Answer 1

Average rate of change = (d (5) - d (2)) / (5 - 2) = (16 (5) ^2 - 16 (2) ^2) / 3 = 336 / 3 = 112.

Therefore, the average rate of change of d (t) from t = 2 to t = 5 represents that the ball travels an average distance of 112 feet from 2 seconds to 5 seconds.