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6 May, 17:06

Solving systems using substitution

2) y = x + 8

y = - 4x - 12

4) y = 3x - 4

y = x - 4

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Answers (2)
  1. 6 May, 17:15
    0
    Answer: Daddy oh yeah
  2. 6 May, 17:26
    0
    2) x=-4 y=4 4) x=0 y=-4

    Step-by-step explanation:

    2) Step: Substitute x+8 for y in y=-4x-12:

    y=-4x-12

    x+8=-4x-12

    x+8+4x=-4x-12+4x (Add 4x to both sides)

    5x+8=-12

    5x+8+-8=-12+-8 (Add - 8 to both sides)

    5x=-20

    5x / 5 = - 20 / 5 (Divide both sides by 5)

    x=-4

    Step: Substitute - 4 for x in y=x+8:

    y=x+8

    y=-4+8

    y=4 (Simplify both sides of the equation)

    Answer:

    x=-4 and y=4

    4) Step: Substitute 3x-4 for y in y=x-4:

    y=x-4

    3x-4=x-4

    3x-4+-x=x-4+-x (Add - x to both sides)

    2x-4=-4

    2x-4+4=-4+4 (Add 4 to both sides)

    2x=0

    2x/2 = 0 / 2 (Divide both sides by 2)

    x=0

    Step: Substitute 0 for x in y=3x-4:

    y=3x-4

    y = (3) (0) - 4

    y=-4 (Simplify both sides of the equation)

    Answer:

    x=0 and y=-4
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