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13 November, 05:12

How do i solve Sec^2x+2secx=0

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  1. 13 November, 05:22
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    Let sec x = a

    sec^2 x + 2sec x = 0

    => a^2 + 2a = 0

    => a (a + 2) = 0

    => a = 0 or a + 2 = 0

    a = - 2

    i. e. sec x = - 2

    1/cos x = - 2

    -2cos x = 1

    cos x = - 1/2

    x = cos^ (-1) (-1/2) = 2pi/3
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