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Salas
Mathematics
13 November, 05:12
How do i solve Sec^2x+2secx=0
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Robertson
13 November, 05:22
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Let sec x = a
sec^2 x + 2sec x = 0
=> a^2 + 2a = 0
=> a (a + 2) = 0
=> a = 0 or a + 2 = 0
a = - 2
i. e. sec x = - 2
1/cos x = - 2
-2cos x = 1
cos x = - 1/2
x = cos^ (-1) (-1/2) = 2pi/3
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