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18 July, 15:51

Two positive integers $m$ and $n$ are chosen such that $m$ is the smallest positive integer with only two positive divisors and $n$ is the largest integer less than $100$ with exactly three positive divisors. What is $m+n$?

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Answers (2)
  1. 18 July, 16:04
    0
    M=3

    (3,1)

    n=77

    (1,11,7)

    so m+n=80
  2. 18 July, 16:04
    0
    Hello,

    we only have 3 divisors if n is a square of a prime (1, a, a²) with a<10

    ==>n=49

    and m=2

    m+n=49+2=51
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