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Laurel
Mathematics
18 July, 03:53
A+b+c=18, b+c=10, c-b=6
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Sarai Jenkins
18 July, 04:18
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C-b=6
solve for c
c=b+6
substitute b+6 for c
b+c=10
b + (b+6) = 10
2b=4
b=2
substitute that in to find C
c-b=6
c-2=6
c=8
a+b+c=18
a+2+8=18
a+10=18
a=8
so a=8, b=2, c=8
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