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Mathematics
4 February, 03:03
What is the solution set of 8x^2 - 2x - 1 = 0
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Ernest Mckay
4 February, 03:21
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Step-by-step explanation:
4x^2 - 8x > = 0
Factor left side
4x (x - 2) >=0
Then case I) 4x <=0 and x - 2 < = 0
so x < = 0 and x < = 2
So x < = 0
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