If the quadratic formula is used to solve 2x 2 - 3x - 1 = 0, what are the solutions?

Question

Denisse Rocha

Mathematics

29 July, 05:45

If the quadratic formula is used to solve 2x 2 - 3x - 1 = 0, what are the solutions?

+5

Answers (2)

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Damian Delacruz · Answer 1

The quadratic formula used to solve a quadratic of the form ax^2+bx+c is:

x = (-b±√ (b^2-4ac)) / (2a) so in this case:

x = (3±√ (9+8)) / 4

x = (3±√17) / 4

Owen Leach · Answer 2

(2x - 1) (x - 1) = 0

by the zero property which must be stated!

2x-1=0 or x-1=0

2x=+1 or x = + 1

x = 1/2

a = 2 b = - 3 c = + 1

+3+-√ (9 - 4*2*1) / 4

+3+-√ 1/4

3+-1/4 = 1/2 or + 1 as we found earlier