Solve the system using the elimination method.

2x + 2y + 5z = - 1

2x - y + z = 2

2x + 4y - 3z = 14

What x, y, and z?

Multiplying the first equation by - 1 and adding it to the third, we get 2y-8z=15 and by multiplying the first equation by - 1 and adding it to the second equation, we get - 3y-4z=3

Using the two equations, we have

2y-8z=15

-3y-4z=3

Multiplying the second equation by - 2 and adding it to the third, we have 8y=9 and y = 9/8 by dividing both sides by 8. Plugging it back into

-3y-4z=3, we have - 27/8-4z=3 and by adding 27/8 to both sides, we have - 4z=51/8 and by dividing both sides by - 4 we get z=-51/32.

Plugging it into 2x - y + z = 2, we get 2x-9/8+5 (-51/32) = 2, we get x=151/64 by adding - (5 (-51/32)) to both sides as well as adding 9/8 to both.