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6 July, 03:58

How many complex roots does the equation below have? X^6+x^3+1=0

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  1. 6 July, 04:14
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    If you find the discriminant it will tell you the number and types of roots. The discriminant is the value b^2 - 4ac.

    a = 1

    b = 1

    c = 1

    1^2 - 4*1*1

    1-4 = - 3

    Since this is a negative number there will be 2 complex roots.
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