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10 April, 13:43

A singing contest eliminates contestants after each round. The number of contestants that go into round n is equal to the number of contestants in the previous round raised to the n-1/n -th power, rounded to the nearest integer. The number of contestants in Round 2 is 243. How many contestants will be in Round 5?

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  1. 10 April, 13:58
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    9

    Step-by-step explanation:

    Since we know the number of contestants in Round 2, we could go step by step and calculate the number of remaining contestants in Round 3, then Round 4 and finally Round 5.

    However, we can do it without calculating. So in Round 3, there will be:

    R3 = R2^ ((n-1) / n), where n is number of the round

    R3 = R2^ (2/3)

    For Round 4, the number will be:

    R4 = (R2^ (2/3)) ^ (3/4)

    And Round 5 will be:

    R5 = ((R2^ (2/3)) ^ (3/4)) ^ (4/5)

    Threes and fives in exponents will cancel out and we'll remain only with:

    R5 = R2^ (2/5)

    R5 = 249^ (2/5)

    R5 = 9.08

    Rounded to the nearest integer, the number of contestants in Round 5 is 9.
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