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25 February, 18:47

Integral of (3x-2) / (x-1) ^2

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  1. 25 February, 19:06
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    (3x-2) / (x-1) ^2 = A / (x-1) + B/x (x-1) ^2

    =[ A (x-1) + Bx (x-1) ] / 2 3x-2=A (x-1) + Bx

    3x-2=x (A+B) - A

    A+B=3

    -A=-2=>A=2

    A+B=3=>2+B=3=>B=1

    lets check our partial fraction we have 2 / (x-1) + x / (x-1) ^2 = [ 2 (x-1) + x] / (x-1) ^2

    = (3x-2) / (x-1) ^2
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