A golf ball is hit with an initial velocity of 50 m/s at an angle of 45° above the horizontal. What's the maximum height it will reach?

a. 35.4 m

b. 63.5 m

c. 82.1 m

d. 127.0 m

This problem is a projectile problem. The initial velocity is 50m/s at an optimum angle of 45. The maximum height or the height of the y component is at it's highest is asked.

Informtion needed:

Acceleration due to gravity = 9.81m/s^2

Formula:

Hmax = ((V^2) (sin (angle)) ^2) / 2g

Hmax = ((50^2) (sin45) ^2) / (2*9.81) = 63.71 or letter B 63.5 m is the closest answer.