The original price P for a necklace is the same at both jewelry stores. At Store A, the sale price is 60% of the original price. Last month, at Store B, the sale rice was $40 less than the original price. This month, Store B is selling the necklace for 80% of last months reduced price. The current sale prices are the same for both stores. Write and solve an equation to find the original price of the necklace.

Question

Quinten Parrish

Mathematics

22 December, 10:58

The original price P for a necklace is the same at both jewelry stores. At Store A, the sale price is 60% of the original price. Last month, at Store B, the sale rice was $40 less than the original price. This month, Store B is selling the necklace for 80% of last months reduced price. The current sale prices are the same for both stores. Write and solve an equation to find the original price of the necklace.

+1

Answers (1)

Know the Answer?

Claudia Salazar · Answer 1

Let the original price of the necklace be 'x'

Store A's price = 60% of x = 0.6x

Store B's price (last month) = x - 40

Store B's price (this month) = 80% of (x - 40) = 0.8 (x - 40)

Store A's price = Store B's price

0.6x = 0.8 (x - 40)

0.6x = 0.8x - 32

32 = 0.8x - 0.6x

32 = 0.2x

x = 32:0.2

x = 160

Original price of the necklace is $160